Anyone know Calc? Need help

[Sean]

What the hell does this mean? I missed a day of class and this was the homework. I can't get to class anytime between now and the time it is due to see a tutor and my instructor does not offer help via email. Can someone decipher this for me?

PLEASE!!

[TRAZ]

Wow......it has been way too long since my last math class....sorry bro!

[Mighty Mouse]

here. not sure if its right.

first two pics, one of them is answer to number 1. not sure.

second is number two. but i wasn't sure if you missed a number in the question on accident. first equation of ^7sqrt[4x^5] looks funny, shouldn't there be a number in front of the ^7, what is the power of 7 the power of 7 of since there is no number or variable below it?

[Mighty Mouse]

also, read this, I assume this is what was discussed in the class that you missed.


http://www.sosmath.com/calculus/inte.../rational.html

you can use the things talked about on that page to find your own answers to the problems yo have listed, I didn't feel like it so I used an online Integrator, so mine might be wrong. but if you use the instructions on that page you should come up with the answers.

[Sean]

Originally Posted by Mighty Mouse

here. not sure if its right.

first two pics, one of them is answer to number 1. not sure.

second is number two. but i wasn't sure if you missed a number in the question on accident. first equation of ^7sqrt[4x^5] looks funny, shouldn't there be a number in front of the ^7, what is the power of 7 the power of 7 of since there is no number or variable below it?

Nope, that is the equation. The sq is raised to power of 7 I believe.
Thanks for the help and the link MM, A hero again.

[Caferacer]

Originally Posted by Sean

Nope, that is the equation. The sq is raised to power of 7 I believe.
Thanks for the help and the link MM, A hero again.

Alright here I go. I'm going to explain as best I can how to do the problems.

The power integration formula is just
Integral(X^N) = (X^N+1)/(N+1)
So something like Integral(X) would be (X^2)/2 since X is to the one power, correct?

Now, you have powers in the demoninator. All this means is that if it is 1/X, it can be rewritten as X^-1. 1/X^2 would be X^-2. Once you realize this, integrating them is easy as the integration power formula still applies to them. Just remember that the 1/4 still has a X variable, it is just to the zero power (X^0 = 1, so this is true).

For the other problem, the forumla Integral(X^N) = (X^N+1)/(N+1) still applies! But when you take the 7th root, you are raising the variable to the 1/7 power. The square root is just to the 1/2 power. For something like in your example, 4X^5 to the 7th root, it can be rewritten as this: 4^1/7 * X^5/7.

4^1/7 is just a coefficient so it stays next to the X^5/7, and you can integrate X^5/7 using the same method as the last problem. You would end up with:

((4^1/7)*(X^12/7))/(12/7)

I hope that makes it a little easier. It's a ***** typing out math on forums, if you think about how I wrote it like how you would type it on a TI-83 or 89 it will be easier to see.

[Mighty Mouse]

Originally Posted by Sean

Nope, that is the equation. The sq is raised to power of 7 I believe.
Thanks for the help and the link MM, A hero again.

ok, cool. I wasn't sure, I thought the sq was raised, but the online integrator didn't support that, but the other link is a good informative link and you should be ble to work it from there.

have fun.

[Sean]

And there are folks who think lifters are dumb...shyot.
You guys are great. I think I understand it now.
Thanks.